Base | Representation |
---|---|
bin | 1011101101001111010… |
… | …1000111111001011101 |
3 | 201020010120022020021201 |
4 | 2323103311013321131 |
5 | 11243344314223143 |
6 | 232221103155501 |
7 | 20350000212352 |
oct | 2732365077135 |
9 | 636116266251 |
10 | 201122414173 |
11 | 783283a561a |
12 | 32b8b5a5b91 |
13 | 15c72a1a085 |
14 | 9a3d1b6629 |
15 | 5371c8664d |
hex | 2ed3d47e5d |
201122414173 has 2 divisors, whose sum is σ = 201122414174. Its totient is φ = 201122414172.
The previous prime is 201122414137. The next prime is 201122414183. The reversal of 201122414173 is 371414221102.
Together with previous prime (201122414137) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 200966613849 + 155800324 = 448293^2 + 12482^2 .
It is a cyclic number.
It is not a de Polignac number, because 201122414173 - 217 = 201122283101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201122414113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100561207086 + 100561207087.
It is an arithmetic number, because the mean of its divisors is an integer number (100561207087).
Almost surely, 2201122414173 is an apocalyptic number.
It is an amenable number.
201122414173 is a deficient number, since it is larger than the sum of its proper divisors (1).
201122414173 is an equidigital number, since it uses as much as digits as its factorization.
201122414173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 201122414173 its reverse (371414221102), we get a palindrome (572536635275).
The spelling of 201122414173 in words is "two hundred one billion, one hundred twenty-two million, four hundred fourteen thousand, one hundred seventy-three".
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