Base | Representation |
---|---|
bin | 1001001001010101111110… |
… | …00100001011100011001101 |
3 | 2122012201012202101102111001 |
4 | 10210222333010023203031 |
5 | 10114004333030032023 |
6 | 110435234150500301 |
7 | 4144030054623445 |
oct | 444527704134315 |
9 | 78181182342431 |
10 | 20112242424013 |
11 | 6454610583533 |
12 | 2309a79364691 |
13 | b2b76524724c |
14 | 4d761b1a3125 |
15 | 24d273c7a6ad |
hex | 124abf10b8cd |
20112242424013 has 2 divisors, whose sum is σ = 20112242424014. Its totient is φ = 20112242424012.
The previous prime is 20112242423927. The next prime is 20112242424067. The reversal of 20112242424013 is 31042424221102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10848242306889 + 9264000117124 = 3293667^2 + 3043682^2 .
It is a cyclic number.
It is not a de Polignac number, because 20112242424013 - 29 = 20112242423501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20112242424713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056121212006 + 10056121212007.
It is an arithmetic number, because the mean of its divisors is an integer number (10056121212007).
Almost surely, 220112242424013 is an apocalyptic number.
It is an amenable number.
20112242424013 is a deficient number, since it is larger than the sum of its proper divisors (1).
20112242424013 is an equidigital number, since it uses as much as digits as its factorization.
20112242424013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 20112242424013 its reverse (31042424221102), we get a palindrome (51154666645115).
The spelling of 20112242424013 in words is "twenty trillion, one hundred twelve billion, two hundred forty-two million, four hundred twenty-four thousand, thirteen".
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