Base | Representation |
---|---|
bin | 11101010001000110101… |
… | …110101010001110000011 |
3 | 21010021100011120120221211 |
4 | 131101012232222032003 |
5 | 230423000210044303 |
6 | 4135540311230551 |
7 | 265210121146633 |
oct | 35210656521603 |
9 | 7107304516854 |
10 | 2011231331203 |
11 | 705a5a721196 |
12 | 285959378457 |
13 | 117873395b93 |
14 | 6d4b637a6c3 |
15 | 374b401466d |
hex | 1d446baa383 |
2011231331203 has 2 divisors, whose sum is σ = 2011231331204. Its totient is φ = 2011231331202.
The previous prime is 2011231331149. The next prime is 2011231331257. The reversal of 2011231331203 is 3021331321102.
It is a balanced prime because it is at equal distance from previous prime (2011231331149) and next prime (2011231331257).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011231331203 is a prime.
It is a super-2 number, since 2×20112313312032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2011231361203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005615665601 + 1005615665602.
It is an arithmetic number, because the mean of its divisors is an integer number (1005615665602).
Almost surely, 22011231331203 is an apocalyptic number.
2011231331203 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011231331203 is an equidigital number, since it uses as much as digits as its factorization.
2011231331203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 2011231331203 its reverse (3021331321102), we get a palindrome (5032562652305).
The spelling of 2011231331203 in words is "two trillion, eleven billion, two hundred thirty-one million, three hundred thirty-one thousand, two hundred three".
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