Base | Representation |
---|---|
bin | 11101010001001011011… |
… | …010111000011000100111 |
3 | 21010021112122200000201211 |
4 | 131101023122320120213 |
5 | 230423130332014143 |
6 | 4135552202132251 |
7 | 265212065123356 |
oct | 35211332703047 |
9 | 7107478600654 |
10 | 2011310032423 |
11 | 705aa009561a |
12 | 28597b7b1087 |
13 | 117886790053 |
14 | 6d4c29c599d |
15 | 374badad49d |
hex | 1d44b6b8627 |
2011310032423 has 2 divisors, whose sum is σ = 2011310032424. Its totient is φ = 2011310032422.
The previous prime is 2011310032409. The next prime is 2011310032447. The reversal of 2011310032423 is 3242300131102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011310032423 - 213 = 2011310024231 is a prime.
It is a super-2 number, since 2×20113100324232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2011310032394 and 2011310032403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011310032453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005655016211 + 1005655016212.
It is an arithmetic number, because the mean of its divisors is an integer number (1005655016212).
Almost surely, 22011310032423 is an apocalyptic number.
2011310032423 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011310032423 is an equidigital number, since it uses as much as digits as its factorization.
2011310032423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 2011310032423 its reverse (3242300131102), we get a palindrome (5253610163525).
The spelling of 2011310032423 in words is "two trillion, eleven billion, three hundred ten million, thirty-two thousand, four hundred twenty-three".
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