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2011331030117 is a prime number
BaseRepresentation
bin11101010001001100101…
…010111110110001100101
321010021121010011211011012
4131101030222332301211
5230423201220430432
64135554232152005
7265212441446213
oct35211452766145
97107533154135
102011331030117
11706000a27492
12285986838605
1311788ac32616
146d4c56cdcb3
15374bcb59cb2
hex1d44cabec65

2011331030117 has 2 divisors, whose sum is σ = 2011331030118. Its totient is φ = 2011331030116.

The previous prime is 2011331030063. The next prime is 2011331030147. The reversal of 2011331030117 is 7110301331102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1015195289761 + 996135740356 = 1007569^2 + 998066^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011331030117 - 26 = 2011331030053 is a prime.

It is a super-2 number, since 2×20113310301172 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2011331030092 and 2011331030101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2011331030147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005665515058 + 1005665515059.

It is an arithmetic number, because the mean of its divisors is an integer number (1005665515059).

Almost surely, 22011331030117 is an apocalyptic number.

It is an amenable number.

2011331030117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011331030117 is an equidigital number, since it uses as much as digits as its factorization.

2011331030117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 23.

Adding to 2011331030117 its reverse (7110301331102), we get a palindrome (9121632361219).

The spelling of 2011331030117 in words is "two trillion, eleven billion, three hundred thirty-one million, thirty thousand, one hundred seventeen".