Base | Representation |
---|---|
bin | 11101010001001100101… |
… | …011110010000100111011 |
3 | 21010021121010120111101221 |
4 | 131101030223302010323 |
5 | 230423201244142001 |
6 | 4135554240452511 |
7 | 265212443312644 |
oct | 35211453620473 |
9 | 7107533514357 |
10 | 2011331240251 |
11 | 706001060353 |
12 | 28598691a137 |
13 | 11788aca7168 |
14 | 6d4c57466cb |
15 | 374bcb9c1a1 |
hex | 1d44caf213b |
2011331240251 has 2 divisors, whose sum is σ = 2011331240252. Its totient is φ = 2011331240250.
The previous prime is 2011331240213. The next prime is 2011331240309. The reversal of 2011331240251 is 1520421331102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011331240251 - 221 = 2011329143099 is a prime.
It is not a weakly prime, because it can be changed into another prime (2011331240201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005665620125 + 1005665620126.
It is an arithmetic number, because the mean of its divisors is an integer number (1005665620126).
Almost surely, 22011331240251 is an apocalyptic number.
2011331240251 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011331240251 is an equidigital number, since it uses as much as digits as its factorization.
2011331240251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 2011331240251 its reverse (1520421331102), we get a palindrome (3531752571353).
The spelling of 2011331240251 in words is "two trillion, eleven billion, three hundred thirty-one million, two hundred forty thousand, two hundred fifty-one".
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