Base | Representation |
---|---|
bin | 1001001001011000010101… |
… | …11100101111011110001101 |
3 | 2122012211111110222112121101 |
4 | 10210230022330233132031 |
5 | 10114014434434324123 |
6 | 110440004350103101 |
7 | 4144103444144056 |
oct | 444541274573615 |
9 | 78184443875541 |
10 | 20113515542413 |
11 | 64551041901a7 |
12 | 230a1737aaa91 |
13 | b2b908c2c747 |
14 | 4d76dc2c772d |
15 | 24d2ea90aaad |
hex | 124b0af2f78d |
20113515542413 has 2 divisors, whose sum is σ = 20113515542414. Its totient is φ = 20113515542412.
The previous prime is 20113515542347. The next prime is 20113515542429. The reversal of 20113515542413 is 31424551531102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14119572790404 + 5993942752009 = 3757602^2 + 2448253^2 .
It is a cyclic number.
It is not a de Polignac number, because 20113515542413 - 221 = 20113513445261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20113515542213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056757771206 + 10056757771207.
It is an arithmetic number, because the mean of its divisors is an integer number (10056757771207).
Almost surely, 220113515542413 is an apocalyptic number.
It is an amenable number.
20113515542413 is a deficient number, since it is larger than the sum of its proper divisors (1).
20113515542413 is an equidigital number, since it uses as much as digits as its factorization.
20113515542413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 37.
The spelling of 20113515542413 in words is "twenty trillion, one hundred thirteen billion, five hundred fifteen million, five hundred forty-two thousand, four hundred thirteen".
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