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2011410412441 is a prime number
BaseRepresentation
bin11101010001010001011…
…001110011001110011001
321010021210122112212020021
4131101101121303032121
5230423332031144231
64140010145430441
7265214424260443
oct35212131631631
97107718485207
102011410412441
11706041816611
122859a933b421
131178a1507801
146d4d2075493
15374c4ada811
hex1d451673399

2011410412441 has 2 divisors, whose sum is σ = 2011410412442. Its totient is φ = 2011410412440.

The previous prime is 2011410412379. The next prime is 2011410412447. The reversal of 2011410412441 is 1442140141102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1917590722441 + 93819690000 = 1384771^2 + 306300^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011410412441 - 215 = 2011410379673 is a prime.

It is not a weakly prime, because it can be changed into another prime (2011410412447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005705206220 + 1005705206221.

It is an arithmetic number, because the mean of its divisors is an integer number (1005705206221).

Almost surely, 22011410412441 is an apocalyptic number.

It is an amenable number.

2011410412441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011410412441 is an equidigital number, since it uses as much as digits as its factorization.

2011410412441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1024, while the sum is 25.

Adding to 2011410412441 its reverse (1442140141102), we get a palindrome (3453550553543).

The spelling of 2011410412441 in words is "two trillion, eleven billion, four hundred ten million, four hundred twelve thousand, four hundred forty-one".