Base | Representation |
---|---|
bin | 11101010001010001100… |
… | …001011011101010111101 |
3 | 21010021210210022111122101 |
4 | 131101101201123222331 |
5 | 230423333034204432 |
6 | 4140010300345101 |
7 | 265214450262352 |
oct | 35212141335275 |
9 | 7107723274571 |
10 | 2011412413117 |
11 | 706042962768 |
12 | 2859a9b45191 |
13 | 1178a1a58343 |
14 | 6d4d2436629 |
15 | 374c4d834e7 |
hex | 1d45185babd |
2011412413117 has 2 divisors, whose sum is σ = 2011412413118. Its totient is φ = 2011412413116.
The previous prime is 2011412413039. The next prime is 2011412413139. The reversal of 2011412413117 is 7113142141102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1912077762841 + 99334650276 = 1382779^2 + 315174^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011412413117 - 215 = 2011412380349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011412419117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005706206558 + 1005706206559.
It is an arithmetic number, because the mean of its divisors is an integer number (1005706206559).
Almost surely, 22011412413117 is an apocalyptic number.
It is an amenable number.
2011412413117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011412413117 is an equidigital number, since it uses as much as digits as its factorization.
2011412413117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 28.
Adding to 2011412413117 its reverse (7113142141102), we get a palindrome (9124554554219).
The spelling of 2011412413117 in words is "two trillion, eleven billion, four hundred twelve million, four hundred thirteen thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •