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2011412413117 is a prime number
BaseRepresentation
bin11101010001010001100…
…001011011101010111101
321010021210210022111122101
4131101101201123222331
5230423333034204432
64140010300345101
7265214450262352
oct35212141335275
97107723274571
102011412413117
11706042962768
122859a9b45191
131178a1a58343
146d4d2436629
15374c4d834e7
hex1d45185babd

2011412413117 has 2 divisors, whose sum is σ = 2011412413118. Its totient is φ = 2011412413116.

The previous prime is 2011412413039. The next prime is 2011412413139. The reversal of 2011412413117 is 7113142141102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1912077762841 + 99334650276 = 1382779^2 + 315174^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011412413117 - 215 = 2011412380349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2011412419117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005706206558 + 1005706206559.

It is an arithmetic number, because the mean of its divisors is an integer number (1005706206559).

Almost surely, 22011412413117 is an apocalyptic number.

It is an amenable number.

2011412413117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011412413117 is an equidigital number, since it uses as much as digits as its factorization.

2011412413117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 28.

Adding to 2011412413117 its reverse (7113142141102), we get a palindrome (9124554554219).

The spelling of 2011412413117 in words is "two trillion, eleven billion, four hundred twelve million, four hundred thirteen thousand, one hundred seventeen".