Base | Representation |
---|---|
bin | 1001001001011101001011… |
… | …01101011101001100000011 |
3 | 2122020002012102200110002112 |
4 | 10210232211231131030003 |
5 | 10114040244133110333 |
6 | 110441114141205535 |
7 | 4144225002536342 |
oct | 444564555351403 |
9 | 78202172613075 |
10 | 20116112003843 |
11 | 6456216889099 |
12 | 230a7792608ab |
13 | b2bc30b33b5b |
14 | 4d78a7087b59 |
15 | 24d3ed83c948 |
hex | 124ba5b5d303 |
20116112003843 has 2 divisors, whose sum is σ = 20116112003844. Its totient is φ = 20116112003842.
The previous prime is 20116112003797. The next prime is 20116112003879. The reversal of 20116112003843 is 34830021161102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20116112003843 - 218 = 20116111741699 is a prime.
It is not a weakly prime, because it can be changed into another prime (20116112003243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10058056001921 + 10058056001922.
It is an arithmetic number, because the mean of its divisors is an integer number (10058056001922).
Almost surely, 220116112003843 is an apocalyptic number.
20116112003843 is a deficient number, since it is larger than the sum of its proper divisors (1).
20116112003843 is an equidigital number, since it uses as much as digits as its factorization.
20116112003843 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 32.
Adding to 20116112003843 its reverse (34830021161102), we get a palindrome (54946133164945).
The spelling of 20116112003843 in words is "twenty trillion, one hundred sixteen billion, one hundred twelve million, three thousand, eight hundred forty-three".
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