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20116112307047 is a prime number
BaseRepresentation
bin1001001001011101001011…
…01110100111001101100111
32122020002012110020212000022
410210232211232213031213
510114040244222311142
6110441114151505355
74144225005241331
oct444564556471547
978202173225008
1020116112307047
116456216a75979
12230a77938825b
13b2bc30c0bb73
144d78a7126451
1524d3ed89c6d2
hex124ba5ba7367

20116112307047 has 2 divisors, whose sum is σ = 20116112307048. Its totient is φ = 20116112307046.

The previous prime is 20116112307013. The next prime is 20116112307073. The reversal of 20116112307047 is 74070321161102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20116112307047 - 234 = 20098932437863 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20116112306998 and 20116112307016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20116112307007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10058056153523 + 10058056153524.

It is an arithmetic number, because the mean of its divisors is an integer number (10058056153524).

Almost surely, 220116112307047 is an apocalyptic number.

20116112307047 is a deficient number, since it is larger than the sum of its proper divisors (1).

20116112307047 is an equidigital number, since it uses as much as digits as its factorization.

20116112307047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14112, while the sum is 35.

Adding to 20116112307047 its reverse (74070321161102), we get a palindrome (94186433468149).

The spelling of 20116112307047 in words is "twenty trillion, one hundred sixteen billion, one hundred twelve million, three hundred seven thousand, forty-seven".