Base | Representation |
---|---|
bin | 101101101111110110000111… |
… | …110010101101110011101111 |
3 | 222101101112102102020020122011 |
4 | 231233312013302231303233 |
5 | 202332430120411400421 |
6 | 1551530002544302051 |
7 | 60244136042235463 |
oct | 5557660762556357 |
9 | 871345372206564 |
10 | 201200021200111 |
11 | 591214a476a39a |
12 | 1a695ab4011927 |
13 | 883610808a31b |
14 | 37981c0caa4a3 |
15 | 183da1aa664e1 |
hex | b6fd87cadcef |
201200021200111 has 2 divisors, whose sum is σ = 201200021200112. Its totient is φ = 201200021200110.
The previous prime is 201200021200099. The next prime is 201200021200153. The reversal of 201200021200111 is 111002120002102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201200021200111 - 29 = 201200021199599 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201200021200091 and 201200021200100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201200021230111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100600010600055 + 100600010600056.
It is an arithmetic number, because the mean of its divisors is an integer number (100600010600056).
Almost surely, 2201200021200111 is an apocalyptic number.
201200021200111 is a deficient number, since it is larger than the sum of its proper divisors (1).
201200021200111 is an equidigital number, since it uses as much as digits as its factorization.
201200021200111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 201200021200111 its reverse (111002120002102), we get a palindrome (312202141202213).
The spelling of 201200021200111 in words is "two hundred one trillion, two hundred billion, twenty-one million, two hundred thousand, one hundred eleven".
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