Base | Representation |
---|---|
bin | 11101010001110100100… |
… | …110101101111010010111 |
3 | 21010100022210211212120201 |
4 | 131101310212231322113 |
5 | 230431034224013421 |
6 | 4140144524041331 |
7 | 265235155221343 |
oct | 35216446557227 |
9 | 7110283755521 |
10 | 2012001001111 |
11 | 706315126622 |
12 | 285b33093247 |
13 | 11796698976a |
14 | 6d54a68c623 |
15 | 3750b899b91 |
hex | 1d4749ade97 |
2012001001111 has 4 divisors (see below), whose sum is σ = 2036241977112. Its totient is φ = 1987760025112.
The previous prime is 2012001001103. The next prime is 2012001001117. The reversal of 2012001001111 is 1111001002102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2012001001111 - 23 = 2012001001103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2012001001117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12120487876 + ... + 12120488041.
It is an arithmetic number, because the mean of its divisors is an integer number (509060494278).
Almost surely, 22012001001111 is an apocalyptic number.
2012001001111 is a deficient number, since it is larger than the sum of its proper divisors (24240976001).
2012001001111 is an equidigital number, since it uses as much as digits as its factorization.
2012001001111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24240976000.
The product of its (nonzero) digits is 4, while the sum is 10.
Adding to 2012001001111 its reverse (1111001002102), we get a palindrome (3123002003213).
Subtracting from 2012001001111 its reverse (1111001002102), we obtain a palindrome (900999999009).
The spelling of 2012001001111 in words is "two trillion, twelve billion, one million, one thousand, one hundred eleven".
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