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2012001001111 = 8324240975917
BaseRepresentation
bin11101010001110100100…
…110101101111010010111
321010100022210211212120201
4131101310212231322113
5230431034224013421
64140144524041331
7265235155221343
oct35216446557227
97110283755521
102012001001111
11706315126622
12285b33093247
1311796698976a
146d54a68c623
153750b899b91
hex1d4749ade97

2012001001111 has 4 divisors (see below), whose sum is σ = 2036241977112. Its totient is φ = 1987760025112.

The previous prime is 2012001001103. The next prime is 2012001001117. The reversal of 2012001001111 is 1111001002102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2012001001111 - 23 = 2012001001103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2012001001117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12120487876 + ... + 12120488041.

It is an arithmetic number, because the mean of its divisors is an integer number (509060494278).

Almost surely, 22012001001111 is an apocalyptic number.

2012001001111 is a deficient number, since it is larger than the sum of its proper divisors (24240976001).

2012001001111 is an equidigital number, since it uses as much as digits as its factorization.

2012001001111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24240976000.

The product of its (nonzero) digits is 4, while the sum is 10.

Adding to 2012001001111 its reverse (1111001002102), we get a palindrome (3123002003213).

Subtracting from 2012001001111 its reverse (1111001002102), we obtain a palindrome (900999999009).

The spelling of 2012001001111 in words is "two trillion, twelve billion, one million, one thousand, one hundred eleven".

Divisors: 1 83 24240975917 2012001001111