Search a number
-
+
2012002200181 is a prime number
BaseRepresentation
bin11101010001110100101…
…011010010101001110101
321010100022220002210101201
4131101310223102221311
5230431040030401211
64140145005452501
7265235201344231
oct35216453225165
97110286083351
102012002200181
11706315875496
12285b33571131
13117966cb947c
146d54a8c15c1
153750ba350c1
hex1d474ad2a75

2012002200181 has 2 divisors, whose sum is σ = 2012002200182. Its totient is φ = 2012002200180.

The previous prime is 2012002200107. The next prime is 2012002200233. The reversal of 2012002200181 is 1810022002102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1838668200625 + 173333999556 = 1355975^2 + 416334^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012002200181 is a prime.

It is a super-2 number, since 2×20120022001812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2012002200281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006001100090 + 1006001100091.

It is an arithmetic number, because the mean of its divisors is an integer number (1006001100091).

Almost surely, 22012002200181 is an apocalyptic number.

It is an amenable number.

2012002200181 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012002200181 is an equidigital number, since it uses as much as digits as its factorization.

2012002200181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 2012002200181 its reverse (1810022002102), we get a palindrome (3822024202283).

The spelling of 2012002200181 in words is "two trillion, twelve billion, two million, two hundred thousand, one hundred eighty-one".