Base | Representation |
---|---|
bin | 1001001001100100101000… |
… | …01000101100000110000101 |
3 | 2122020110112012121102011002 |
4 | 10210302110020230012011 |
5 | 10114121442200321242 |
6 | 110443015113423045 |
7 | 4144426064136215 |
oct | 444622410540605 |
9 | 78213465542132 |
10 | 20120112120197 |
11 | 6457989841781 |
12 | 230b4b4a0aa85 |
13 | b2c41a7964cb |
14 | 4d7b6642c245 |
15 | 24d584ad7432 |
hex | 124c9422c185 |
20120112120197 has 2 divisors, whose sum is σ = 20120112120198. Its totient is φ = 20120112120196.
The previous prime is 20120112120191. The next prime is 20120112120259. The reversal of 20120112120197 is 79102121102102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13526279040481 + 6593833079716 = 3677809^2 + 2567846^2 .
It is a cyclic number.
It is not a de Polignac number, because 20120112120197 - 224 = 20120095342981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20120112120191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060056060098 + 10060056060099.
It is an arithmetic number, because the mean of its divisors is an integer number (10060056060099).
Almost surely, 220120112120197 is an apocalyptic number.
It is an amenable number.
20120112120197 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120112120197 is an equidigital number, since it uses as much as digits as its factorization.
20120112120197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 29.
Adding to 20120112120197 its reverse (79102121102102), we get a palindrome (99222233222299).
The spelling of 20120112120197 in words is "twenty trillion, one hundred twenty billion, one hundred twelve million, one hundred twenty thousand, one hundred ninety-seven".
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