Base | Representation |
---|---|
bin | 1001001001100100110010… |
… | …11111100101110110100110 |
3 | 2122020110202110202021210212 |
4 | 10210302121133211312212 |
5 | 10114122133203310042 |
6 | 110443032044215422 |
7 | 4144431235162532 |
oct | 444623137456646 |
9 | 78213673667725 |
10 | 20120202010022 |
11 | 6457a25558294 |
12 | 230b51ab3a572 |
13 | b2c4332aa25a |
14 | 4d7b7434abc2 |
15 | 24d58c941482 |
hex | 124c997e5da6 |
20120202010022 has 4 divisors (see below), whose sum is σ = 30180303015036. Its totient is φ = 10060101005010.
The previous prime is 20120202009931. The next prime is 20120202010037. The reversal of 20120202010022 is 22001020202102.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×201202020100223 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20120202009979 and 20120202010006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5030050502504 + ... + 5030050502507.
It is an arithmetic number, because the mean of its divisors is an integer number (7545075753759).
Almost surely, 220120202010022 is an apocalyptic number.
20120202010022 is a deficient number, since it is larger than the sum of its proper divisors (10060101005014).
20120202010022 is a wasteful number, since it uses less digits than its factorization.
20120202010022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10060101005013.
The product of its (nonzero) digits is 64, while the sum is 14.
Adding to 20120202010022 its reverse (22001020202102), we get a palindrome (42121222212124).
The spelling of 20120202010022 in words is "twenty trillion, one hundred twenty billion, two hundred two million, ten thousand, twenty-two".
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