201202100051 has 2 divisors, whose sum is σ = 201202100052. Its totient is φ = 201202100050.

The previous prime is 201202100003. The next prime is 201202100053. The reversal of 201202100051 is 150001202102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201202100051 is a prime.

It is a super-2 number, since 2×201202100051² (a number of 23 digits) contains 22 as substring.

Together with 201202100053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 201202099999 and 201202100035.

It is not a weakly prime, because it can be changed into another prime (201202100053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100601050025 + 100601050026.

It is an arithmetic number, because the mean of its divisors is an integer number (100601050026).

Almost surely, 2^201202100051 is an apocalyptic number.

201202100051 is a deficient number, since it is larger than the sum of its proper divisors (1).

201202100051 is an equidigital number, since it uses as much as digits as its factorization.

201202100051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40, while the sum is 14.

Adding to 201202100051 its reverse (150001202102), we get a palindrome (351203302153).

The spelling of 201202100051 in words is "two hundred one billion, two hundred two million, one hundred thousand, fifty-one".