Base | Representation |
---|---|
bin | 1001001001100100110011… |
… | …11110000111011101110001 |
3 | 2122020110210000210211111001 |
4 | 10210302121332013131301 |
5 | 10114122142230341032 |
6 | 110443032531522001 |
7 | 4144431363201133 |
oct | 444623176073561 |
9 | 78213700724431 |
10 | 20120210012017 |
11 | 6457a2a023305 |
12 | 230b521759301 |
13 | b2c434b4c56b |
14 | 4d7b75431053 |
15 | 24d58d4c23e7 |
hex | 124c99f87771 |
20120210012017 has 2 divisors, whose sum is σ = 20120210012018. Its totient is φ = 20120210012016.
The previous prime is 20120210012003. The next prime is 20120210012033. The reversal of 20120210012017 is 71021001202102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10593456148081 + 9526753863936 = 3254759^2 + 3086544^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20120210012017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20120210011985 and 20120210012003.
It is not a weakly prime, because it can be changed into another prime (20120210012087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060105006008 + 10060105006009.
It is an arithmetic number, because the mean of its divisors is an integer number (10060105006009).
Almost surely, 220120210012017 is an apocalyptic number.
It is an amenable number.
20120210012017 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120210012017 is an equidigital number, since it uses as much as digits as its factorization.
20120210012017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 20120210012017 its reverse (71021001202102), we get a palindrome (91141211214119).
The spelling of 20120210012017 in words is "twenty trillion, one hundred twenty billion, two hundred ten million, twelve thousand, seventeen".
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