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201203050423 is a prime number
BaseRepresentation
bin1011101101100010100…
…0101110011110110111
3201020100012000222102111
42323120220232132313
511244030440103143
6232233103351451
720351666465434
oct2733050563667
9636305028374
10201203050423
1178369970851
1232bb25b2587
1315c86640c2b
149a49ba6b8b
155378db399d
hex2ed8a2e7b7

201203050423 has 2 divisors, whose sum is σ = 201203050424. Its totient is φ = 201203050422.

The previous prime is 201203050381. The next prime is 201203050457. The reversal of 201203050423 is 324050302102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201203050423 - 29 = 201203049911 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201203050394 and 201203050403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201203050493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100601525211 + 100601525212.

It is an arithmetic number, because the mean of its divisors is an integer number (100601525212).

Almost surely, 2201203050423 is an apocalyptic number.

201203050423 is a deficient number, since it is larger than the sum of its proper divisors (1).

201203050423 is an equidigital number, since it uses as much as digits as its factorization.

201203050423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 22.

Adding to 201203050423 its reverse (324050302102), we get a palindrome (525253352525).

The spelling of 201203050423 in words is "two hundred one billion, two hundred three million, fifty thousand, four hundred twenty-three".