Search a number
-
+
201210012000097 is a prime number
BaseRepresentation
bin101101101111111111011011…
…010010100101111101100001
3222101102111012200200110201021
4231233333123102211331201
5202333111101033000342
61551534334202005441
760244641445522312
oct5557773322457541
9871374180613637
10201210012000097
1159125761270291
121a697a21aa6881
13883703aba60a9
14379888bb16609
15183de02c08567
hexb6ffdb4a5f61

201210012000097 has 2 divisors, whose sum is σ = 201210012000098. Its totient is φ = 201210012000096.

The previous prime is 201210011999951. The next prime is 201210012000119. The reversal of 201210012000097 is 790000210012102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 194414610973696 + 6795401026401 = 13943264^2 + 2606799^2 .

It is a cyclic number.

It is not a de Polignac number, because 201210012000097 - 215 = 201210011967329 is a prime.

It is not a weakly prime, because it can be changed into another prime (201210012000497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605006000048 + 100605006000049.

It is an arithmetic number, because the mean of its divisors is an integer number (100605006000049).

Almost surely, 2201210012000097 is an apocalyptic number.

It is an amenable number.

201210012000097 is a deficient number, since it is larger than the sum of its proper divisors (1).

201210012000097 is an equidigital number, since it uses as much as digits as its factorization.

201210012000097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 201210012000097 its reverse (790000210012102), we get a palindrome (991210222012199).

The spelling of 201210012000097 in words is "two hundred one trillion, two hundred ten billion, twelve million, ninety-seven", and thus it is an aban number.