Base | Representation |
---|---|
bin | 101101101111111111100000… |
… | …100110001001011010110011 |
3 | 222101102111102220011202021212 |
4 | 231233333200212021122303 |
5 | 202333111241324342042 |
6 | 1551534351101510335 |
7 | 60244643606231543 |
oct | 5557774046113263 |
9 | 871374386152255 |
10 | 201210101012147 |
11 | 591257a7537367 |
12 | 1a697a478723ab |
13 | 8837053470446 |
14 | 3798899887323 |
15 | 183de0a93c482 |
hex | b6ffe09896b3 |
201210101012147 has 2 divisors, whose sum is σ = 201210101012148. Its totient is φ = 201210101012146.
The previous prime is 201210101012077. The next prime is 201210101012149. The reversal of 201210101012147 is 741210101012102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201210101012147 - 222 = 201210096817843 is a prime.
Together with 201210101012149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (201210101012149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605050506073 + 100605050506074.
It is an arithmetic number, because the mean of its divisors is an integer number (100605050506074).
Almost surely, 2201210101012147 is an apocalyptic number.
201210101012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
201210101012147 is an equidigital number, since it uses as much as digits as its factorization.
201210101012147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 201210101012147 its reverse (741210101012102), we get a palindrome (942420202024249).
The spelling of 201210101012147 in words is "two hundred one trillion, two hundred ten billion, one hundred one million, twelve thousand, one hundred forty-seven".
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