Base | Representation |
---|---|
bin | 101101101111111111100111… |
… | …101100011110100010000011 |
3 | 222101102111202012021122120122 |
4 | 231233333213230132202003 |
5 | 202333112012322041003 |
6 | 1551534410554330455 |
7 | 60244646553453464 |
oct | 5557774754364203 |
9 | 871374665248518 |
10 | 201210220112003 |
11 | 591258587938a3 |
12 | 1a697a7b729a2b |
13 | 883707204072b |
14 | 37988ab60ad6b |
15 | 183de16116238 |
hex | b6ffe7b1e883 |
201210220112003 has 2 divisors, whose sum is σ = 201210220112004. Its totient is φ = 201210220112002.
The previous prime is 201210220111931. The next prime is 201210220112039. The reversal of 201210220112003 is 300211022012102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201210220112003 is a prime.
It is not a weakly prime, because it can be changed into another prime (201210220112303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605110056001 + 100605110056002.
It is an arithmetic number, because the mean of its divisors is an integer number (100605110056002).
Almost surely, 2201210220112003 is an apocalyptic number.
201210220112003 is a deficient number, since it is larger than the sum of its proper divisors (1).
201210220112003 is an equidigital number, since it uses as much as digits as its factorization.
201210220112003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 201210220112003 its reverse (300211022012102), we get a palindrome (501421242124105).
The spelling of 201210220112003 in words is "two hundred one trillion, two hundred ten billion, two hundred twenty million, one hundred twelve thousand, three".
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