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201210244434113 is a prime number
BaseRepresentation
bin101101101111111111101001…
…001001010000100011000001
3222101102111210220001100020112
4231233333221021100203001
5202333112040033342423
61551534413223521105
760244650300263435
oct5557775111204301
9871374726040215
10201210244434113
1159125870496412
121a697a878b9195
1388370770a8205
1437988b093c9c5
15183de1831ca78
hexb6ffe92508c1

201210244434113 has 2 divisors, whose sum is σ = 201210244434114. Its totient is φ = 201210244434112.

The previous prime is 201210244434047. The next prime is 201210244434127. The reversal of 201210244434113 is 311434442012102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 192947879362624 + 8262365071489 = 13890568^2 + 2874433^2 .

It is a cyclic number.

It is not a de Polignac number, because 201210244434113 - 28 = 201210244433857 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 201210244434113.

It is not a weakly prime, because it can be changed into another prime (201210244434163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605122217056 + 100605122217057.

It is an arithmetic number, because the mean of its divisors is an integer number (100605122217057).

Almost surely, 2201210244434113 is an apocalyptic number.

It is an amenable number.

201210244434113 is a deficient number, since it is larger than the sum of its proper divisors (1).

201210244434113 is an equidigital number, since it uses as much as digits as its factorization.

201210244434113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 201210244434113 its reverse (311434442012102), we get a palindrome (512644686446215).

The spelling of 201210244434113 in words is "two hundred one trillion, two hundred ten billion, two hundred forty-four million, four hundred thirty-four thousand, one hundred thirteen".