Base | Representation |
---|---|
bin | 10010101111010011… |
… | …111001111101110111 |
3 | 1220221021101210102112 |
4 | 102233103321331313 |
5 | 312202000201101 |
6 | 13124333001235 |
7 | 1311422346365 |
oct | 225723717567 |
9 | 56837353375 |
10 | 20121100151 |
11 | 8595922399 |
12 | 3a9662321b |
13 | 1b887c8529 |
14 | d8c40a635 |
15 | 7cb6dc6bb |
hex | 4af4f9f77 |
20121100151 has 2 divisors, whose sum is σ = 20121100152. Its totient is φ = 20121100150.
The previous prime is 20121100117. The next prime is 20121100163. The reversal of 20121100151 is 15100112102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20121100151 - 218 = 20120838007 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20121100651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060550075 + 10060550076.
It is an arithmetic number, because the mean of its divisors is an integer number (10060550076).
Almost surely, 220121100151 is an apocalyptic number.
20121100151 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121100151 is an equidigital number, since it uses as much as digits as its factorization.
20121100151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 20121100151 its reverse (15100112102), we get a palindrome (35221212253).
The spelling of 20121100151 in words is "twenty billion, one hundred twenty-one million, one hundred thousand, one hundred fifty-one".
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