Base | Representation |
---|---|
bin | 11101010001111011000… |
… | …110111001011010001111 |
3 | 21010100121102010200021102 |
4 | 131101323012321122033 |
5 | 230431300141200421 |
6 | 4140203422253315 |
7 | 265240651441256 |
oct | 35217306713217 |
9 | 7110542120242 |
10 | 2012110100111 |
11 | 706370772291 |
12 | 285b6372723b |
13 | 117983467997 |
14 | 6d55ad6b79d |
15 | 3751624a60b |
hex | 1d47b1b968f |
2012110100111 has 2 divisors, whose sum is σ = 2012110100112. Its totient is φ = 2012110100110.
The previous prime is 2012110100009. The next prime is 2012110100131. The reversal of 2012110100111 is 1110010112102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012110100111 - 218 = 2012109837967 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 2012110100092 and 2012110100101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012110100131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006055050055 + 1006055050056.
It is an arithmetic number, because the mean of its divisors is an integer number (1006055050056).
Almost surely, 22012110100111 is an apocalyptic number.
2012110100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012110100111 is an equidigital number, since it uses as much as digits as its factorization.
2012110100111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 2012110100111 its reverse (1110010112102), we get a palindrome (3122120212213).
The spelling of 2012110100111 in words is "two trillion, twelve billion, one hundred ten million, one hundred thousand, one hundred eleven".
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