Base | Representation |
---|---|
bin | 11101010001111011001… |
… | …010011010001111001011 |
3 | 21010100121110212110111112 |
4 | 131101323022122033023 |
5 | 230431300410133003 |
6 | 4140203454120535 |
7 | 265240662325136 |
oct | 35217312321713 |
9 | 7110543773445 |
10 | 2012111021003 |
11 | 706371241156 |
12 | 285b63ab014b |
13 | 1179836caba5 |
14 | 6d55b12b21d |
15 | 3751637d3d8 |
hex | 1d47b29a3cb |
2012111021003 has 2 divisors, whose sum is σ = 2012111021004. Its totient is φ = 2012111021002.
The previous prime is 2012111020981. The next prime is 2012111021087. The reversal of 2012111021003 is 3001201112102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012111021003 - 210 = 2012111019979 is a prime.
It is not a weakly prime, because it can be changed into another prime (2012111021803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006055510501 + 1006055510502.
It is an arithmetic number, because the mean of its divisors is an integer number (1006055510502).
Almost surely, 22012111021003 is an apocalyptic number.
2012111021003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012111021003 is an equidigital number, since it uses as much as digits as its factorization.
2012111021003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 2012111021003 its reverse (3001201112102), we get a palindrome (5013312133105).
The spelling of 2012111021003 in words is "two trillion, twelve billion, one hundred eleven million, twenty-one thousand, three".
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