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2012112102103 is a prime number
BaseRepresentation
bin11101010001111011001…
…110100010001011010111
321010100121112220101111021
4131101323032202023113
5230431301144231403
64140203533222011
7265241004450055
oct35217316421327
97110545811437
102012112102103
1170637190a424
12285b64331907
131179839b8cac
146d55b32d1d5
15375164e38bd
hex1d47b3a22d7

2012112102103 has 2 divisors, whose sum is σ = 2012112102104. Its totient is φ = 2012112102102.

The previous prime is 2012112102073. The next prime is 2012112102151. The reversal of 2012112102103 is 3012012112102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2012112102103 - 213 = 2012112093911 is a prime.

It is a super-2 number, since 2×20121121021032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2012112102163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006056051051 + 1006056051052.

It is an arithmetic number, because the mean of its divisors is an integer number (1006056051052).

Almost surely, 22012112102103 is an apocalyptic number.

2012112102103 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012112102103 is an equidigital number, since it uses as much as digits as its factorization.

2012112102103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 2012112102103 its reverse (3012012112102), we get a palindrome (5024124214205).

Subtracting 2012112102103 from its reverse (3012012112102), we obtain a palindrome (999900009999).

The spelling of 2012112102103 in words is "two trillion, twelve billion, one hundred twelve million, one hundred two thousand, one hundred three".