Base | Representation |
---|---|
bin | 1001001001100110100000… |
… | …10001101101111110010011 |
3 | 2122020120010112012220212121 |
4 | 10210303100101231332103 |
5 | 10114131024001321042 |
6 | 110443303200035111 |
7 | 4144463065403065 |
oct | 444632021557623 |
9 | 78216115186777 |
10 | 20121121120147 |
11 | 6458357352333 |
12 | 230b736902a97 |
13 | b2c54b834cb8 |
14 | 4d7c2043d735 |
15 | 24d5e3495367 |
hex | 124cd046df93 |
20121121120147 has 2 divisors, whose sum is σ = 20121121120148. Its totient is φ = 20121121120146.
The previous prime is 20121121119997. The next prime is 20121121120169. The reversal of 20121121120147 is 74102112112102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20121121120147 is a prime.
It is not a weakly prime, because it can be changed into another prime (20121121120547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060560560073 + 10060560560074.
It is an arithmetic number, because the mean of its divisors is an integer number (10060560560074).
Almost surely, 220121121120147 is an apocalyptic number.
20121121120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121121120147 is an equidigital number, since it uses as much as digits as its factorization.
20121121120147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 25.
Adding to 20121121120147 its reverse (74102112112102), we get a palindrome (94223233232249).
The spelling of 20121121120147 in words is "twenty trillion, one hundred twenty-one billion, one hundred twenty-one million, one hundred twenty thousand, one hundred forty-seven".
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