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2012113113120 = 2532511617205879
BaseRepresentation
bin11101010001111011010…
…010011001000000100000
321010100121121210202100100
4131101323102121000200
5230431301424104440
64140204011022400
7265241016160455
oct35217322310040
97110547722310
102012113113120
1170637243aa80
12285b6473aa00
13117983c81226
146d55b51382c
1537516643230
hex1d47b499020

2012113113120 has 288 divisors, whose sum is σ = 7502725077120. Its totient is φ = 486992056320.

The previous prime is 2012113113103. The next prime is 2012113113151. The reversal of 2012113113120 is 213113112102.

2012113113120 is a `hidden beast` number, since 20 + 1 + 21 + 1 + 311 + 312 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (288).

It is a super-2 number, since 2×20121131131202 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 2012113113093 and 2012113113102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9670341 + ... + 9876219.

It is an arithmetic number, because the mean of its divisors is an integer number (26051128740).

Almost surely, 22012113113120 is an apocalyptic number.

2012113113120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2012113113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3751362538560).

2012113113120 is an abundant number, since it is smaller than the sum of its proper divisors (5490611964000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2012113113120 is a wasteful number, since it uses less digits than its factorization.

2012113113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 206528 (or 206517 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 2012113113120 its reverse (213113112102), we get a palindrome (2225226225222).

The spelling of 2012113113120 in words is "two trillion, twelve billion, one hundred thirteen million, one hundred thirteen thousand, one hundred twenty".