Base | Representation |
---|---|
bin | 11101010001111011010… |
… | …010110000110100000111 |
3 | 21010100121121222201002212 |
4 | 131101323102300310013 |
5 | 230431301440220011 |
6 | 4140204013054035 |
7 | 265241020044656 |
oct | 35217322606407 |
9 | 7110547881085 |
10 | 2012113210631 |
11 | 7063724a7267 |
12 | 285b6478731b |
13 | 117983cb6724 |
14 | 6d55b53b19d |
15 | 3751666208b |
hex | 1d47b4b0d07 |
2012113210631 has 2 divisors, whose sum is σ = 2012113210632. Its totient is φ = 2012113210630.
The previous prime is 2012113210607. The next prime is 2012113210663. The reversal of 2012113210631 is 1360123112102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012113210631 - 210 = 2012113209607 is a prime.
It is a super-2 number, since 2×20121132106312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2012113210597 and 2012113210606.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012113210831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006056605315 + 1006056605316.
It is an arithmetic number, because the mean of its divisors is an integer number (1006056605316).
Almost surely, 22012113210631 is an apocalyptic number.
2012113210631 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012113210631 is an equidigital number, since it uses as much as digits as its factorization.
2012113210631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 2012113210631 its reverse (1360123112102), we get a palindrome (3372236322733).
The spelling of 2012113210631 in words is "two trillion, twelve billion, one hundred thirteen million, two hundred ten thousand, six hundred thirty-one".
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