Base | Representation |
---|---|
bin | 11101010001111011110… |
… | …001010100001110101101 |
3 | 21010100122012001121220122 |
4 | 131101323301110032231 |
5 | 230431311013020023 |
6 | 4140204500454325 |
7 | 265241145113642 |
oct | 35217361241655 |
9 | 7110565047818 |
10 | 2012121220013 |
11 | 706376a77893 |
12 | 285b673aa3a5 |
13 | 11798585c1c8 |
14 | 6d55c623dc9 |
15 | 375171e52c8 |
hex | 1d47bc543ad |
2012121220013 has 4 divisors (see below), whose sum is σ = 2050085771388. Its totient is φ = 1974156668640.
The previous prime is 2012121220009. The next prime is 2012121220037. The reversal of 2012121220013 is 3100221212102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 859510701604 + 1152610518409 = 927098^2 + 1073597^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012121220013 - 22 = 2012121220009 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2012121219973 and 2012121220000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2012121270013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18982275608 + ... + 18982275713.
It is an arithmetic number, because the mean of its divisors is an integer number (512521442847).
Almost surely, 22012121220013 is an apocalyptic number.
It is an amenable number.
2012121220013 is a deficient number, since it is larger than the sum of its proper divisors (37964551375).
2012121220013 is an equidigital number, since it uses as much as digits as its factorization.
2012121220013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37964551374.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2012121220013 its reverse (3100221212102), we get a palindrome (5112342432115).
The spelling of 2012121220013 in words is "two trillion, twelve billion, one hundred twenty-one million, two hundred twenty thousand, thirteen".
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