Base | Representation |
---|---|
bin | 10010101111010100… |
… | …010101100001001001 |
3 | 1220221021121112020011 |
4 | 102233110111201021 |
5 | 312202012304001 |
6 | 13124335231521 |
7 | 1311423326401 |
oct | 225724254111 |
9 | 56837545204 |
10 | 20121213001 |
11 | 859599a15a |
12 | 3a966785a1 |
13 | 1b888379c6 |
14 | d8c439801 |
15 | 7cb710d51 |
hex | 4af515849 |
20121213001 has 2 divisors, whose sum is σ = 20121213002. Its totient is φ = 20121213000.
The previous prime is 20121212963. The next prime is 20121213029. The reversal of 20121213001 is 10031212102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18618875401 + 1502337600 = 136451^2 + 38760^2 .
It is a cyclic number.
It is not a de Polignac number, because 20121213001 - 219 = 20120688713 is a prime.
It is a super-2 number, since 2×201212130012 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20121211001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060606500 + 10060606501.
It is an arithmetic number, because the mean of its divisors is an integer number (10060606501).
Almost surely, 220121213001 is an apocalyptic number.
It is an amenable number.
20121213001 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121213001 is an equidigital number, since it uses as much as digits as its factorization.
20121213001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 20121213001 its reverse (10031212102), we get a palindrome (30152425103).
The spelling of 20121213001 in words is "twenty billion, one hundred twenty-one million, two hundred thirteen thousand, one".
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