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20121220023 = 373358125657
BaseRepresentation
bin10010101111010100…
…010111001110110111
31220221021121212212020
4102233110113032313
5312202013020043
613124335324223
71311423356022
oct225724271667
956837555766
1020121220023
1185959a4463
123a96680673
131b8883ac68
14d8c43c1b9
157cb712e83
hex4af5173b7

20121220023 has 16 divisors (see below), whose sum is σ = 27204458976. Its totient is φ = 13226181120.

The previous prime is 20121219991. The next prime is 20121220027. The reversal of 20121220023 is 32002212102.

It is a happy number.

It is not a de Polignac number, because 20121220023 - 25 = 20121219991 is a prime.

It is a super-2 number, since 2×201212200232 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20121219984 and 20121220011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20121220027) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 771411 + ... + 797067.

It is an arithmetic number, because the mean of its divisors is an integer number (1700278686).

Almost surely, 220121220023 is an apocalyptic number.

20121220023 is a deficient number, since it is larger than the sum of its proper divisors (7083238953).

20121220023 is a wasteful number, since it uses less digits than its factorization.

20121220023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29314.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 20121220023 its reverse (32002212102), we get a palindrome (52123432125).

The spelling of 20121220023 in words is "twenty billion, one hundred twenty-one million, two hundred twenty thousand, twenty-three".

Divisors: 1 3 73 219 3581 10743 25657 76971 261413 784239 1872961 5618883 91877717 275633151 6707073341 20121220023