Base | Representation |
---|---|
bin | 1001001001100110110001… |
… | …01111100001011111001111 |
3 | 2122020120111102110211122121 |
4 | 10210303120233201133033 |
5 | 10114131321331313210 |
6 | 110443325232153411 |
7 | 4144466441552263 |
oct | 444633057413717 |
9 | 78216442424577 |
10 | 20121263151055 |
11 | 645841a541250 |
12 | 230b776398867 |
13 | b2c5720a3861 |
14 | 4d7c352520a3 |
15 | 24d600b9d6da |
hex | 124cd8be17cf |
20121263151055 has 32 divisors (see below), whose sum is σ = 26371276968960. Its totient is φ = 14616586494720.
The previous prime is 20121263151019. The next prime is 20121263151127. The reversal of 20121263151055 is 55015136212102.
It is not a de Polignac number, because 20121263151055 - 211 = 20121263149007 is a prime.
It is a super-2 number, since 2×201212631510552 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20121263151055.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 496568086 + ... + 496608604.
It is an arithmetic number, because the mean of its divisors is an integer number (824102405280).
Almost surely, 220121263151055 is an apocalyptic number.
20121263151055 is a deficient number, since it is larger than the sum of its proper divisors (6250013817905).
20121263151055 is a wasteful number, since it uses less digits than its factorization.
20121263151055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50839.
The product of its (nonzero) digits is 18000, while the sum is 34.
Adding to 20121263151055 its reverse (55015136212102), we get a palindrome (75136399363157).
The spelling of 20121263151055 in words is "twenty trillion, one hundred twenty-one billion, two hundred sixty-three million, one hundred fifty-one thousand, fifty-five".
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