Base | Representation |
---|---|
bin | 11101010001111100010… |
… | …010111000101010101011 |
3 | 21010100122210121201020111 |
4 | 131101330102320222223 |
5 | 230431320241120021 |
6 | 4140205413235151 |
7 | 265241312654626 |
oct | 35217422705253 |
9 | 7110583551214 |
10 | 2012130020011 |
11 | 706380a38411 |
12 | 285b6a332ab7 |
13 | 1179876207c7 |
14 | 6d55d874dbd |
15 | 37517d828e1 |
hex | 1d47c4b8aab |
2012130020011 has 2 divisors, whose sum is σ = 2012130020012. Its totient is φ = 2012130020010.
The previous prime is 2012130019979. The next prime is 2012130020053. The reversal of 2012130020011 is 1100200312102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012130020011 - 25 = 2012130019979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2012130019973 and 2012130020000.
It is not a weakly prime, because it can be changed into another prime (2012130023011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006065010005 + 1006065010006.
It is an arithmetic number, because the mean of its divisors is an integer number (1006065010006).
Almost surely, 22012130020011 is an apocalyptic number.
2012130020011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012130020011 is an equidigital number, since it uses as much as digits as its factorization.
2012130020011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 2012130020011 its reverse (1100200312102), we get a palindrome (3112330332113).
The spelling of 2012130020011 in words is "two trillion, twelve billion, one hundred thirty million, twenty thousand, eleven".
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