Base | Representation |
---|---|
bin | 1001001001100111000010… |
… | …00010000101000100111011 |
3 | 2122020120212010011221102012 |
4 | 10210303201002011010323 |
5 | 10114132112432430042 |
6 | 110443351121200135 |
7 | 4144503051000365 |
oct | 444634102050473 |
9 | 78216763157365 |
10 | 20121402233147 |
11 | 6458490aa6726 |
12 | 230b7b4a9004b |
13 | b2c594b4c157 |
14 | 4d7c498d7d35 |
15 | 24d60cec2e82 |
hex | 124ce108513b |
20121402233147 has 2 divisors, whose sum is σ = 20121402233148. Its totient is φ = 20121402233146.
The previous prime is 20121402233143. The next prime is 20121402233221. The reversal of 20121402233147 is 74133220412102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20121402233147 - 22 = 20121402233143 is a prime.
It is not a weakly prime, because it can be changed into another prime (20121402233143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060701116573 + 10060701116574.
It is an arithmetic number, because the mean of its divisors is an integer number (10060701116574).
Almost surely, 220121402233147 is an apocalyptic number.
20121402233147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121402233147 is an equidigital number, since it uses as much as digits as its factorization.
20121402233147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 20121402233147 its reverse (74133220412102), we get a palindrome (94254622645249).
The spelling of 20121402233147 in words is "twenty trillion, one hundred twenty-one billion, four hundred two million, two hundred thirty-three thousand, one hundred forty-seven".
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