201214131401 has 2 divisors, whose sum is σ = 201214131402. Its totient is φ = 201214131400.

The previous prime is 201214131383. The next prime is 201214131403. The reversal of 201214131401 is 104131412102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 201188131600 + 25999801 = 448540^2 + 5099^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201214131401 is a prime.

Together with 201214131403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (201214131403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100607065700 + 100607065701.

It is an arithmetic number, because the mean of its divisors is an integer number (100607065701).

Almost surely, 2^201214131401 is an apocalyptic number.

It is an amenable number.

201214131401 is a deficient number, since it is larger than the sum of its proper divisors (1).

201214131401 is an equidigital number, since it uses as much as digits as its factorization.

201214131401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 201214131401 its reverse (104131412102), we get a palindrome (305345543503).

The spelling of 201214131401 in words is "two hundred one billion, two hundred fourteen million, one hundred thirty-one thousand, four hundred one".