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2012200020013 is a prime number
BaseRepresentation
bin11101010010000000011…
…101111010100000101101
321010100211200100002012011
4131102000131322200231
5230431441201120023
64140220353441221
7265243122651361
oct35220035724055
97110750302164
102012200020013
117064074a9457
12285b89870211
13117998c8c321
146d568c972a1
153751e0ad50d
hex1d48077a82d

2012200020013 has 2 divisors, whose sum is σ = 2012200020014. Its totient is φ = 2012200020012.

The previous prime is 2012200020007. The next prime is 2012200020059. The reversal of 2012200020013 is 3100200022102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1638149129604 + 374050890409 = 1279902^2 + 611597^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012200020013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2012200019975 and 2012200020002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2012200020073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006100010006 + 1006100010007.

It is an arithmetic number, because the mean of its divisors is an integer number (1006100010007).

Almost surely, 22012200020013 is an apocalyptic number.

It is an amenable number.

2012200020013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012200020013 is an equidigital number, since it uses as much as digits as its factorization.

2012200020013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 2012200020013 its reverse (3100200022102), we get a palindrome (5112400042115).

The spelling of 2012200020013 in words is "two trillion, twelve billion, two hundred million, twenty thousand, thirteen".