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20122122113 is a prime number
BaseRepresentation
bin10010101111010111…
…110011011110000001
31220221100022201021222
4102233113303132001
5312202230401423
613124410524425
71311434134022
oct225727633601
956840281258
1020122122113
118596460195
123a96a36715
131b88a95742
14d8c5d4c49
157cb8403c8
hex4af5f3781

20122122113 has 2 divisors, whose sum is σ = 20122122114. Its totient is φ = 20122122112.

The previous prime is 20122122109. The next prime is 20122122133. The reversal of 20122122113 is 31122122102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11382115969 + 8740006144 = 106687^2 + 93488^2 .

It is a cyclic number.

It is not a de Polignac number, because 20122122113 - 22 = 20122122109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20122122091 and 20122122100.

It is not a weakly prime, because it can be changed into another prime (20122122133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061061056 + 10061061057.

It is an arithmetic number, because the mean of its divisors is an integer number (10061061057).

Almost surely, 220122122113 is an apocalyptic number.

It is an amenable number.

20122122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20122122113 is an equidigital number, since it uses as much as digits as its factorization.

20122122113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 20122122113 its reverse (31122122102), we get a palindrome (51244244215).

The spelling of 20122122113 in words is "twenty billion, one hundred twenty-two million, one hundred twenty-two thousand, one hundred thirteen".