Base | Representation |
---|---|
bin | 10010101111010111… |
… | …110011011110000001 |
3 | 1220221100022201021222 |
4 | 102233113303132001 |
5 | 312202230401423 |
6 | 13124410524425 |
7 | 1311434134022 |
oct | 225727633601 |
9 | 56840281258 |
10 | 20122122113 |
11 | 8596460195 |
12 | 3a96a36715 |
13 | 1b88a95742 |
14 | d8c5d4c49 |
15 | 7cb8403c8 |
hex | 4af5f3781 |
20122122113 has 2 divisors, whose sum is σ = 20122122114. Its totient is φ = 20122122112.
The previous prime is 20122122109. The next prime is 20122122133. The reversal of 20122122113 is 31122122102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11382115969 + 8740006144 = 106687^2 + 93488^2 .
It is a cyclic number.
It is not a de Polignac number, because 20122122113 - 22 = 20122122109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20122122091 and 20122122100.
It is not a weakly prime, because it can be changed into another prime (20122122133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061061056 + 10061061057.
It is an arithmetic number, because the mean of its divisors is an integer number (10061061057).
Almost surely, 220122122113 is an apocalyptic number.
It is an amenable number.
20122122113 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122122113 is an equidigital number, since it uses as much as digits as its factorization.
20122122113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 20122122113 its reverse (31122122102), we get a palindrome (51244244215).
The spelling of 20122122113 in words is "twenty billion, one hundred twenty-two million, one hundred twenty-two thousand, one hundred thirteen".
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