Base | Representation |
---|---|
bin | 11101010010000001101… |
… | …010100101101111001011 |
3 | 21010100220002011021012112 |
4 | 131102001222211233023 |
5 | 230432011322320021 |
6 | 4140222352332535 |
7 | 265243455545063 |
oct | 35220152455713 |
9 | 7110802137175 |
10 | 2012220120011 |
11 | 706417887922 |
12 | 285b9454414b |
13 | 1179a01a910a |
14 | 6d56b80a3a3 |
15 | 37520c2dd5b |
hex | 1d481aa5bcb |
2012220120011 has 2 divisors, whose sum is σ = 2012220120012. Its totient is φ = 2012220120010.
The previous prime is 2012220120007. The next prime is 2012220120019. The reversal of 2012220120011 is 1100210222102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012220120011 - 22 = 2012220120007 is a prime.
It is a super-3 number, since 3×20122201200113 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (2012220120019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006110060005 + 1006110060006.
It is an arithmetic number, because the mean of its divisors is an integer number (1006110060006).
Almost surely, 22012220120011 is an apocalyptic number.
2012220120011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012220120011 is an equidigital number, since it uses as much as digits as its factorization.
2012220120011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 2012220120011 its reverse (1100210222102), we get a palindrome (3112430342113).
The spelling of 2012220120011 in words is "two trillion, twelve billion, two hundred twenty million, one hundred twenty thousand, eleven".
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