Base | Representation |
---|---|
bin | 11101010010000111001… |
… | …101110001101110101011 |
3 | 21010101010120100202102221 |
4 | 131102013031301232223 |
5 | 230432204141332001 |
6 | 4140235520134511 |
7 | 265245666143362 |
oct | 35220715615653 |
9 | 7111116322387 |
10 | 2012313230251 |
11 | 7064653a2a35 |
12 | 285bbb767437 |
13 | 1179b657992c |
14 | 6d579d267d9 |
15 | 37528ec21a1 |
hex | 1d487371bab |
2012313230251 has 2 divisors, whose sum is σ = 2012313230252. Its totient is φ = 2012313230250.
The previous prime is 2012313230153. The next prime is 2012313230267. The reversal of 2012313230251 is 1520323132102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012313230251 - 235 = 1977953491883 is a prime.
It is a super-3 number, since 3×20123132302513 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2012313200251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006156615125 + 1006156615126.
It is an arithmetic number, because the mean of its divisors is an integer number (1006156615126).
Almost surely, 22012313230251 is an apocalyptic number.
2012313230251 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012313230251 is an equidigital number, since it uses as much as digits as its factorization.
2012313230251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 2012313230251 its reverse (1520323132102), we get a palindrome (3532636362353).
The spelling of 2012313230251 in words is "two trillion, twelve billion, three hundred thirteen million, two hundred thirty thousand, two hundred fifty-one".
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