Base | Representation |
---|---|
bin | 10010101111011011… |
… | …101100110100010001 |
3 | 1220221102020121021221 |
4 | 102233123230310101 |
5 | 312203011042231 |
6 | 13124444445041 |
7 | 1311445616452 |
oct | 225733546421 |
9 | 56842217257 |
10 | 20123143441 |
11 | 8596a98565 |
12 | 3a97249781 |
13 | 1b8906258b |
14 | d8c7bd129 |
15 | 7cb992d11 |
hex | 4af6ecd11 |
20123143441 has 2 divisors, whose sum is σ = 20123143442. Its totient is φ = 20123143440.
The previous prime is 20123143373. The next prime is 20123143451. The reversal of 20123143441 is 14434132102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19908081216 + 215062225 = 141096^2 + 14665^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20123143441 is a prime.
It is a super-2 number, since 2×201231434412 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20123143451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061571720 + 10061571721.
It is an arithmetic number, because the mean of its divisors is an integer number (10061571721).
Almost surely, 220123143441 is an apocalyptic number.
It is an amenable number.
20123143441 is a deficient number, since it is larger than the sum of its proper divisors (1).
20123143441 is an equidigital number, since it uses as much as digits as its factorization.
20123143441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 20123143441 its reverse (14434132102), we get a palindrome (34557275543).
The spelling of 20123143441 in words is "twenty billion, one hundred twenty-three million, one hundred forty-three thousand, four hundred forty-one".
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