Base | Representation |
---|---|
bin | 11101010010001000100… |
… | …010011100011100001101 |
3 | 21010101012010010101022112 |
4 | 131102020202130130031 |
5 | 230432230332102133 |
6 | 4140242031553405 |
7 | 265246355614064 |
oct | 35221042343415 |
9 | 7111163111275 |
10 | 2012335425293 |
11 | 706476982446 |
12 | 28600708b865 |
13 | 1179bb04b1ab |
14 | 6d57cc631db |
15 | 3752ae08648 |
hex | 1d48889c70d |
2012335425293 has 2 divisors, whose sum is σ = 2012335425294. Its totient is φ = 2012335425292.
The previous prime is 2012335425203. The next prime is 2012335425301. The reversal of 2012335425293 is 3925245332102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1667411786089 + 344923639204 = 1291283^2 + 587302^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012335425293 - 218 = 2012335163149 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2012335425293.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012335425203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006167712646 + 1006167712647.
It is an arithmetic number, because the mean of its divisors is an integer number (1006167712647).
Almost surely, 22012335425293 is an apocalyptic number.
It is an amenable number.
2012335425293 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012335425293 is an equidigital number, since it uses as much as digits as its factorization.
2012335425293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 2012335425293 in words is "two trillion, twelve billion, three hundred thirty-five million, four hundred twenty-five thousand, two hundred ninety-three".
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