Base | Representation |
---|---|
bin | 11101010010001100100… |
… | …000011111110001101011 |
3 | 21010101100202102220220221 |
4 | 131102030200133301223 |
5 | 230432344404223111 |
6 | 4140252411230511 |
7 | 265251124652044 |
oct | 35221440376153 |
9 | 7111322386827 |
10 | 2012402023531 |
11 | 70650052a709 |
12 | 286025448437 |
13 | 1179cba98533 |
14 | 6d587a3b8cb |
15 | 37531bb1371 |
hex | 1d48c81fc6b |
2012402023531 has 2 divisors, whose sum is σ = 2012402023532. Its totient is φ = 2012402023530.
The previous prime is 2012402023493. The next prime is 2012402023571. The reversal of 2012402023531 is 1353202042102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012402023531 - 29 = 2012402023019 is a prime.
It is a super-2 number, since 2×20124020235312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2012402023496 and 2012402023505.
It is not a weakly prime, because it can be changed into another prime (2012402023571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006201011765 + 1006201011766.
It is an arithmetic number, because the mean of its divisors is an integer number (1006201011766).
Almost surely, 22012402023531 is an apocalyptic number.
2012402023531 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012402023531 is an equidigital number, since it uses as much as digits as its factorization.
2012402023531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 2012402023531 its reverse (1353202042102), we get a palindrome (3365604065633).
The spelling of 2012402023531 in words is "two trillion, twelve billion, four hundred two million, twenty-three thousand, five hundred thirty-one".
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