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2012402023531 is a prime number
BaseRepresentation
bin11101010010001100100…
…000011111110001101011
321010101100202102220220221
4131102030200133301223
5230432344404223111
64140252411230511
7265251124652044
oct35221440376153
97111322386827
102012402023531
1170650052a709
12286025448437
131179cba98533
146d587a3b8cb
1537531bb1371
hex1d48c81fc6b

2012402023531 has 2 divisors, whose sum is σ = 2012402023532. Its totient is φ = 2012402023530.

The previous prime is 2012402023493. The next prime is 2012402023571. The reversal of 2012402023531 is 1353202042102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2012402023531 - 29 = 2012402023019 is a prime.

It is a super-2 number, since 2×20124020235312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2012402023496 and 2012402023505.

It is not a weakly prime, because it can be changed into another prime (2012402023571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006201011765 + 1006201011766.

It is an arithmetic number, because the mean of its divisors is an integer number (1006201011766).

Almost surely, 22012402023531 is an apocalyptic number.

2012402023531 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012402023531 is an equidigital number, since it uses as much as digits as its factorization.

2012402023531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 2012402023531 its reverse (1353202042102), we get a palindrome (3365604065633).

The spelling of 2012402023531 in words is "two trillion, twelve billion, four hundred two million, twenty-three thousand, five hundred thirty-one".