201300355441021 has 2 divisors, whose sum is σ = 201300355441022. Its totient is φ = 201300355441020.

The previous prime is 201300355440991. The next prime is 201300355441027. The reversal of 201300355441021 is 120144553003102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141955071960100 + 59345283480921 = 11914490^2 + 7703589^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201300355441021 is a prime.

It is a super-3 number, since 3×201300355441021³ (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201300355441027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100650177720510 + 100650177720511.

It is an arithmetic number, because the mean of its divisors is an integer number (100650177720511).

Almost surely, 2^{201300355441021} is an apocalyptic number.

It is an amenable number.

201300355441021 is a deficient number, since it is larger than the sum of its proper divisors (1).

201300355441021 is an equidigital number, since it uses as much as digits as its factorization.

201300355441021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 201300355441021 in words is "two hundred one trillion, three hundred billion, three hundred fifty-five million, four hundred forty-one thousand, twenty-one".