20130110000029 has 2 divisors, whose sum is σ = 20130110000030. Its totient is φ = 20130110000028.

The previous prime is 20130109999997. The next prime is 20130110000059. The reversal of 20130110000029 is 92000001103102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17084044891225 + 3046065108804 = 4133285^2 + 1745298^2 .

It is a cyclic number.

It is not a de Polignac number, because 20130110000029 - 2⁵ = 20130109999997 is a prime.

It is a super-2 number, since 2×20130110000029² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20130109999970 and 20130110000015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130110000059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065055000014 + 10065055000015.

It is an arithmetic number, because the mean of its divisors is an integer number (10065055000015).

Almost surely, 2^{20130110000029} is an apocalyptic number.

It is an amenable number.

20130110000029 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130110000029 is an equidigital number, since it uses as much as digits as its factorization.

20130110000029 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

The spelling of 20130110000029 in words is "twenty trillion, one hundred thirty billion, one hundred ten million, twenty-nine", and thus it is an aban number.