Base | Representation |
---|---|
bin | 11101010010110000110… |
… | …011111110101001100011 |
3 | 21010102221012112202011112 |
4 | 131102300303332221203 |
5 | 230440121321013444 |
6 | 4140433050133535 |
7 | 265302202055564 |
oct | 35226063765143 |
9 | 7112835482145 |
10 | 2013011110499 |
11 | 706793324774 |
12 | 2861754212ab |
13 | 117a9802621c |
14 | 6d6048ac16b |
15 | 3756a3c669e |
hex | 1d4b0cfea63 |
2013011110499 has 2 divisors, whose sum is σ = 2013011110500. Its totient is φ = 2013011110498.
The previous prime is 2013011110441. The next prime is 2013011110541. The reversal of 2013011110499 is 9940111103102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013011110499 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (2013011113499) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006505555249 + 1006505555250.
It is an arithmetic number, because the mean of its divisors is an integer number (1006505555250).
Almost surely, 22013011110499 is an apocalyptic number.
2013011110499 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013011110499 is an equidigital number, since it uses as much as digits as its factorization.
2013011110499 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 32.
The spelling of 2013011110499 in words is "two trillion, thirteen billion, eleven million, one hundred ten thousand, four hundred ninety-nine".
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