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2013011110997 is a prime number
BaseRepresentation
bin11101010010110000110…
…011111110110001010101
321010102221012112202211222
4131102300303332301111
5230440121321022442
64140433050140125
7265302202060205
oct35226063766125
97112835482758
102013011110997
11706793325087
12286175421645
13117a98026513
146d6048ac405
153756a3c68d2
hex1d4b0cfec55

2013011110997 has 2 divisors, whose sum is σ = 2013011110998. Its totient is φ = 2013011110996.

The previous prime is 2013011110963. The next prime is 2013011111053. The reversal of 2013011110997 is 7990111103102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1420420610596 + 592590500401 = 1191814^2 + 769799^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013011110997 - 210 = 2013011109973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013011110697) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006505555498 + 1006505555499.

It is an arithmetic number, because the mean of its divisors is an integer number (1006505555499).

Almost surely, 22013011110997 is an apocalyptic number.

It is an amenable number.

2013011110997 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013011110997 is an equidigital number, since it uses as much as digits as its factorization.

2013011110997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3402, while the sum is 35.

The spelling of 2013011110997 in words is "two trillion, thirteen billion, eleven million, one hundred ten thousand, nine hundred ninety-seven".