Base | Representation |
---|---|
bin | 1011101101111001111… |
… | …0110011001000100101 |
3 | 201020121000112222201001 |
4 | 2323132132303020211 |
5 | 11244231041030313 |
6 | 232250525233301 |
7 | 20354300133340 |
oct | 2733636631045 |
9 | 636530488631 |
10 | 201301111333 |
11 | 7840a258423 |
12 | 3301b402831 |
13 | 15ca0a55c3a |
14 | 9a58c11457 |
15 | 53827d3add |
hex | 2ede7b3225 |
201301111333 has 48 divisors (see below), whose sum is σ = 237826694784. Its totient is φ = 166884157440.
The previous prime is 201301111301. The next prime is 201301111339. The reversal of 201301111333 is 333111103102.
It is not a de Polignac number, because 201301111333 - 25 = 201301111301 is a prime.
It is a super-2 number, since 2×2013011113332 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 201301111333.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201301111339) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 643134385 + ... + 643134697.
It is an arithmetic number, because the mean of its divisors is an integer number (4954722808).
Almost surely, 2201301111333 is an apocalyptic number.
It is an amenable number.
201301111333 is a deficient number, since it is larger than the sum of its proper divisors (36525583451).
201301111333 is an equidigital number, since it uses as much as digits as its factorization.
201301111333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 762 (or 695 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 201301111333 its reverse (333111103102), we get a palindrome (534412214435).
The spelling of 201301111333 in words is "two hundred one billion, three hundred one million, one hundred eleven thousand, three hundred thirty-three".
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