Base | Representation |
---|---|
bin | 101101110001010100010001… |
… | …110100100110111111101111 |
3 | 222101202012101020201101012121 |
4 | 231301110101310212333233 |
5 | 202341104144011400421 |
6 | 1552044243004213411 |
7 | 60254345304120202 |
oct | 5561242164467757 |
9 | 871665336641177 |
10 | 201301121200111 |
11 | 5916036500a7a9 |
12 | 1a6b160a23a267 |
13 | 88427ca74a72a |
14 | 379d052069939 |
15 | 1841486636d41 |
hex | b71511d26fef |
201301121200111 has 4 divisors (see below), whose sum is σ = 201304195550800. Its totient is φ = 201298046849424.
The previous prime is 201301121200097. The next prime is 201301121200117. The reversal of 201301121200111 is 111002121103102.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 201301121200111 - 223 = 201301112811503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201301121200117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1537077126 + ... + 1537208083.
It is an arithmetic number, because the mean of its divisors is an integer number (50326048887700).
Almost surely, 2201301121200111 is an apocalyptic number.
201301121200111 is a deficient number, since it is larger than the sum of its proper divisors (3074350689).
201301121200111 is an equidigital number, since it uses as much as digits as its factorization.
201301121200111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3074350688.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 201301121200111 its reverse (111002121103102), we get a palindrome (312303242303213).
The spelling of 201301121200111 in words is "two hundred one trillion, three hundred one billion, one hundred twenty-one million, two hundred thousand, one hundred eleven".
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